2cos^2x+4sinx=4

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Solution for 2cos^2x+4sinx=4 equation:


Simplifying
2cos2x + 4sinx = 4

Solving
2cos2x + 4insx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4insx' to each side of the equation.
2cos2x + 4insx + -4insx = 4 + -4insx

Combine like terms: 4insx + -4insx = 0
2cos2x + 0 = 4 + -4insx
2cos2x = 4 + -4insx

Divide each side by '2os2x'.
c = 2o-1s-2x-1 + -2ino-1s-1

Simplifying
c = 2o-1s-2x-1 + -2ino-1s-1

Reorder the terms:
c = -2ino-1s-1 + 2o-1s-2x-1

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